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9x^2-6x+5/9=0
We multiply all the terms by the denominator
9x^2*9-6x*9+5=0
Wy multiply elements
81x^2-54x+5=0
a = 81; b = -54; c = +5;
Δ = b2-4ac
Δ = -542-4·81·5
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-36}{2*81}=\frac{18}{162} =1/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+36}{2*81}=\frac{90}{162} =5/9 $
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